Modern PhysicsThe Quantum World

Finite Wells and Tunneling

Wave functions leak into barriers, so a particle can tunnel through one with probability about e^(−2κL).

Not started Jump to practice

A ball rolling toward a hill it can't climb always rolls back. A quantum particle sometimes doesn't: it can appear on the other side of a barrier that is higher than its energy. This tunneling follows from the decaying wave you met with the Schrödinger equation, and it runs a surprising amount of the world: the fusion that powers the Sun, alpha decay of nuclei, flash memory, and the scanning tunneling microscope that images single atoms.

Key idea

Inside a barrier of height $U_0$ and width $L$, a particle of energy $E < U_0$ has a wave function that decays like $e^{-\kappa x}$, with $$\kappa = \frac{\sqrt{2m(U_0 - E)}}{\hbar}.$$ For a barrier that is not too thin, the chance of getting through is about $$T \approx e^{-2\kappa L}.$$ For an electron, $\kappa = 5.12\ \text{nm}^{-1}\times\sqrt{(U_0 - E)/1\ \text{eV}}$.

Why it works

Where $U > E$, the Schrödinger equation becomes $\psi'' = \kappa^2\psi$, so $\psi$ grows or decays exponentially instead of oscillating. Coming from the left, the physical solution decays: across the barrier, the amplitude shrinks by about $e^{-\kappa L}$. On the far side, $E > U$ again and the wave oscillates with that small amplitude. Probability goes as amplitude squared, so $T \approx \left(e^{-\kappa L}\right)^2 = e^{-2\kappa L}$. (A more careful solution adds a factor of order 1 in front; the exponential dominates.) The exponent makes tunneling extremely sensitive to the width and the height of the barrier.
An electron wave (E = 3 eV) meeting a 5 eV barrier. Inside, the wave decays exponentially; what is left on the far side is the transmitted wave. Make the barrier wider and watch the transmission collapse.

Worked examples

Worked example: Through a thin gap

An electron with $E = 3.0$ eV meets a barrier with $U_0 = 5.0$ eV and width 0.50 nm. Estimate the chance it tunnels through.
  1. $\kappa = 5.12\sqrt{2.0}\ \text{nm}^{-1} = 7.24\ \text{nm}^{-1}$.
  2. $2\kappa L = 2(7.24)(0.50) = 7.24$.
  3. $T \approx e^{-7.24} = 7.2 \times 10^{-4}$.

Answer: About 7 in 10,000

Worked example: Twice as wide

What happens to $T$ if the barrier is 1.00 nm wide instead?
  1. The exponent doubles: $2\kappa L = 14.5$.
  2. $T \approx e^{-14.5} = 5.1 \times 10^{-7}$: the old $T$ squared.

Answer: About 1,400 times smaller

Worked example: The scanning tunneling microscope

An STM's tip is held a small distance above a metal; electrons tunnel across a barrier about 4.5 eV high (above their energy). If the gap widens by 0.10 nm, by what factor does the tunneling current fall?
  1. $\kappa = 5.12\sqrt{4.5} = 10.9\ \text{nm}^{-1}$.
  2. The current is proportional to $T$, which changes by $e^{-2\kappa\Delta L} = e^{-2(10.9)(0.10)} = e^{-2.17} = 0.114$.

Answer: It drops to about 1/9; that sensitivity lets an STM map bumps smaller than an atom

Common mistake

Thinking a particle can never be found where its energy is less than the potential energy. Classically, kinetic energy would be negative there, which is impossible. But the wave function does not stop at the edge; it decays over a distance of about $1/\kappa$, and if the barrier is thin it reaches the other side. Check with a number: for $\kappa = 7$ nm⁻¹, the wave is still $e^{-1}$ of its size 0.14 nm into the barrier.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 3 XP.

Loading practice…

Builds on

Leads to

Sources and further reading

  • OpenStax University Physics Volume 3, 7.6 The Quantum Tunneling of Particles through Potential Barriers
  • MIT OpenCourseWare 8.04 Quantum Physics I (Spring 2016)
@teddyrookbook GitHub