Physics 2Thermodynamics

Rate of Heat Conduction

Heat flows through a slab at the rate P = kAΔT/L, so thinner and wider walls pass more.

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You met conduction in Conduction, Convection and Radiation: heat passing through a material from molecule to molecule. Now we ask how fast. Builders, cooks and engineers all need the rate, in joules per second, or watts, and often need to solve the formula for a thickness or an area.

Why it works

Think of heat crossing a slab of thickness $L$ and area $A$. Twice the area is like two slabs side by side, so twice the rate: $P \propto A$. A bigger temperature difference drives heat harder: $P \propto \Delta T$. A thicker slab spreads the same temperature difference over more distance, so each layer passes on less: $P \propto 1/L$. What is left is the material, through its thermal conductivity $k$. In metals, free electrons carry energy quickly, so $k$ is large; in foam, trapped air carries it slowly.

Key idea

$$P = \frac{Q}{t} = \frac{kA\,\Delta T}{L}$$ Thin, wide slabs with big temperature differences pass heat fastest. A temperature difference in $^\circ\text{C}$ is the same number in kelvins.
Conduction through a slab: copper passes heat thousands of times faster than foam.
Approximate thermal conductivities near room temperature.
Material$k$ in $\text{W/(m}\cdot\text{K)}$
Copperabout 390
Aluminumabout 220
Glass, brickabout 0.8
Waterabout 0.6
Woodabout 0.12
Still airabout 0.025
Styrofoamabout 0.010

Worked examples

Worked example: A window

A glass window ($k = 0.84\,\text{W/(m}\cdot\text{K)}$) is $1.2\,\text{m}^2$ in area and $4.0\,\text{mm}$ thick. The inner surface is $15\,^\circ\text{C}$ warmer than the outer surface. Find the rate of heat flow.
  1. Thickness in meters: $L = 0.0040\,\text{m}$. $\Delta T = 15\,\text{K}$.
  2. $P = \dfrac{(0.84)(1.2)(15)}{0.0040} = 3780\,\text{W}$, about $3.8\,\text{kW}$.

Answer: $3.78 \times 10^{3}\,\text{W}$

Worked example: A foam cooler

A styrofoam cooler ($k = 0.010$) has walls $2.0\,\text{cm}$ thick with a total area of $0.80\,\text{m}^2$. Outside is $25\,^\circ\text{C}$ warmer than inside. How fast does heat leak in, and how long until it has delivered enough heat to melt $1.0\,\text{kg}$ of ice ($3.34 \times 10^{5}\,\text{J}$)?
  1. $P = \dfrac{(0.010)(0.80)(25)}{0.020} = 10\,\text{W}$.
  2. $t = \dfrac{Q}{P} = \dfrac{3.34 \times 10^{5}\,\text{J}}{10\,\text{J/s}} = 3.34 \times 10^{4}\,\text{s}$, a bit over nine hours.

Answer: $10\,\text{W}$; about $9.3\,\text{h}$

Common mistake

Thinking a good conductor must be hot. A good conductor is a material that passes heat along quickly, at any temperature. A metal bench and a wooden bench in the same shade are at the same temperature, but the metal feels colder because its large $k$ pulls heat out of your skin faster. Check: temperature tells you which way heat flows; $k$ tells you how fast.
A real single-pane window loses heat more slowly than the first example says, because thin films of still air cling to both sides of the glass and add their own insulation.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

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Builds on

Leads to

This is one of the top rungs of Physics 2: Fluids, Heat, Electricity, Light and Atoms.

Sources and further reading

  • OpenStax, College Physics 2e, section 14.5 Conduction
  • OpenStax, University Physics Volume 2, section 1.6 Mechanisms of Heat Transfer
  • College Board, AP Physics 2 Course and Exam Description, Unit 9: Thermodynamics
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