For centuries, planets around other stars were a guess. The first one around a Sun-like star, 51 Pegasi b, was found in 1995, and today more than 5,000 are confirmed (NASA Exoplanet Archive). Hardly any were seen directly: a planet is billions of times fainter than its star and lost in its glare. Instead astronomers watch the star, using ideas you already know: Doppler shifts and orbits.
💡 Why it works
Transits. If a planet's orbit is edge-on to us, the planet crosses its star's face once per orbit and blocks a small disk of light. The fraction blocked is the ratio of the two disks' areas: $\dfrac{\pi R_p^2}{\pi R_\star^2} = \left(\dfrac{R_p}{R_\star}\right)^2$. The depth gives the planet's size; the time between dips gives its period. Wobble. A star and its planet both orbit their common center of mass, so the star moves in a small circle, and its spectral lines shift back and forth. Balancing momenta, $M_\star v_\star = m_p v_p$, so the size of the wobble gives the planet's mass.
🔑 Key idea
Transit depth $= \left(\dfrac{R_p}{R_\star}\right)^2$ gives a planet's size; the star's Doppler wobble, $v_\star = v_p\,\dfrac{m_p}{M_\star}$, gives its mass. Together they give its density: rocky or gassy.
A planet one-tenth of its star's radius crossing the star. The light curve dips by $0.1^2 = 1\%$.
Worked examples
✏️ Worked example: Jupiter and Earth from afar
Jupiter's radius is about $0.10$ of the Sun's; Earth's is about $\frac{1}{109}$. How much would each dim the Sun during a transit?
Jupiter: $(0.10)^2 = 0.01 = 1\%$.
Earth: $\left(\frac{1}{109}\right)^2 = 8.4 \times 10^{-5}$, about $0.008\%$.
Finding Earth-sized planets needs measuring starlight to better than one part in 10,000, which is why the Kepler and TESS telescopes observe from space.
Answer: $1\%$ and about $0.008\%$.
✏️ Worked example: The Sun's wobble
Jupiter orbits at $13.1$ km/s and has $\frac{1}{1047}$ of the Sun's mass. How fast does Jupiter make the Sun wobble?
That is $12.5$ m/s, about the speed of a fast bicycle, measured from light-years away by its Doppler shift.
Answer: About $12.5$ m/s.
⚠️ Common mistake
It is natural to imagine exoplanets being found in photographs, but only a small share have been imaged directly. Most were found by the transit method (thousands by the Kepler and TESS missions) or by the star's wobble. Check: a planet like Jupiter seen from a nearby star would be about a billion times fainter than the Sun beside it.
A star and a companion circling their center of mass, with the Doppler (radial velocity) curves. A planet makes its star wobble in the same way, only much less.
Practice
Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.