On the celestial sphere we need a way to say where a star is in your sky right now. Two angles do it. Altitude is the angle above the horizon, from $0^\circ$ on the horizon to $90^\circ$ at the zenith. Azimuth is the compass direction, measured from north toward the east: north $0^\circ$, east $90^\circ$, south $180^\circ$, west $270^\circ$.
These angles change as the sky turns and from place to place. One of them is special: the altitude of the celestial pole never changes for you, and it tells you exactly where on Earth you are.
Why it works
Key idea
Worked examples
Worked example: Find your latitude
- The pole's altitude equals the latitude, and Polaris is almost at the pole.
- So the latitude is about $40^\circ$ N.
Answer: $40^\circ$ N.
Worked example: Which stars never set?
- The pole is $40^\circ$ above the northern horizon, so a circle around the pole of radius up to $40^\circ$ stays above the horizon all day.
- The star $30^\circ$ from the pole circles it at a radius of $30^\circ$, dipping no lower than $40^\circ - 30^\circ = 10^\circ$ above the horizon. It never sets.
- The star $50^\circ$ from the pole would dip to $40^\circ - 50^\circ = -10^\circ$: below the horizon. It rises and sets.
- Astronomers give a star's angle north of the celestial equator as its declination $\delta$, so its distance from the pole is $90^\circ - \delta$. Circumpolar at $40^\circ$ N means $\delta \ge 90^\circ - 40^\circ = 50^\circ$.
Answer: The first never sets (circumpolar); the second rises and sets.
The same picture gives a star's highest altitude, when it crosses the meridian: $h_{\max} = 90^\circ - |\text{latitude} - \delta|$. A star whose declination equals your latitude passes straight overhead.
Common mistake