A graph like $y = x^2$ shows a path but not how something travels along it. To describe motion you want to know where an object is at each moment. So let both coordinates depend on a third variable, usually time $t$. You already know the shapes of basic functions and the unit circle; both reappear here.
Key idea
Why it works
Worked examples
Worked example: A table of points
- Make a table: $t = -2$: $(-3, 1)$; $t = -1$: $(-1, -2)$; $t = 0$: $(1, -3)$; $t = 1$: $(3, -2)$; $t = 2$: $(5, 1)$.
- Plot the points in order of $t$ and join them.
- The path is part of a parabola, traced from left to right as $t$ increases.
Answer: A parabolic arc from $(-3, 1)$ to $(5, 1)$, moving rightward
Worked example: Same path, different motion
- Both satisfy $x^2 + y^2 = 1$: the same circle.
- The first starts at $(1, 0)$ and at $t = \frac{\pi}{2}$ is at $(0, 1)$: counterclockwise.
- The second starts at $(0, 1)$ and at $t = \frac{\pi}{2}$ is at $(1, 0)$: clockwise.
Answer: Same circle, opposite directions and different starting points
Worked example: When is it there?
- From $y$: $2t = 4$, so $t = 2$.
- Check $x$: $2^2 - 1 = 3$. ✓ (From $x$ alone, $t = \pm 2$; the $y$-equation picks $t = 2$.)
Answer: $t = 2$
Common mistake