Grade 3Area and Perimeter3.MD.C.7c

Area and the Distributive Property

Split a rectangle in two to find its area in parts.

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You broke apart facts like $7 \times 6 = 5 \times 6 + 2 \times 6$, and you can find the area of a rectangle. Here the two ideas meet: cut a rectangle into two smaller rectangles.

A 6-by-8 rectangle cut into a 6-by-5 part and a 6-by-3 part. $30 + 18 = 48$, the same as $6 \times 8$.

Why it works

Cutting a rectangle does not change how much space it covers. The two pieces together cover exactly the whole. Both pieces are 6 tall, so their areas are $6 \times 5$ and $6 \times 3$. Adding them gives the whole area: $6 \times 8 = 6 \times 5 + 6 \times 3$. This is the same break-apart idea, drawn as area.

Key idea

$a \times (b + c) = a \times b + a \times c$. To find a big area, cut the rectangle into two easier rectangles and add their areas.

Worked example: Cut the long side

Find the area of a 6 by 8 rectangle by cutting 8 into $5 + 3$.
  1. Left part: $6 \times 5 = 30$.
  2. Right part: $6 \times 3 = 18$.
  3. Whole: $30 + 18 = 48$.

Answer: 48 square units

Worked example: Bigger numbers

Find $7 \times 13$ using area.
  1. Cut 13 into $10 + 3$.
  2. $7 \times 10 = 70$ and $7 \times 3 = 21$.
  3. $70 + 21 = 91$.

Answer: 91

Common mistake

Adding a side instead of an area. $6 \times 5 + 3$ leaves out most of the right part: that part is 6 rows of 3, not just 3. Each part is a rectangle, so find each area by multiplying.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

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Sources and further reading

  • Common Core State Standards for Mathematics, Grade 3, 3.MD.C.7c (use area models to represent the distributive property)
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