GeometryQuadrilaterals and Polygons

Polygon Angle Sums

Split a polygon into triangles: (n − 2) × 180°.

Not started Jump to practice

You proved in Triangle Sum and Exterior Angle Proofs that a triangle's angles add to $180^\circ$. Every polygon can be cut into triangles, so the same fact gives the angle sum of any polygon.

Why it works

Interior angles. In a convex polygon with $n$ sides, draw every diagonal from one vertex. They cut it into $n - 2$ triangles (each side except the two at that vertex gets its own triangle), and the triangles' angles together make up exactly the polygon's angles. So the sum is $(n - 2) \cdot 180^\circ$.
Exterior angles. At each vertex, the interior and exterior angles form a linear pair, so all $n$ pairs total $n \cdot 180^\circ$. Subtract the interior sum: $n \cdot 180^\circ - (n - 2) \cdot 180^\circ = 360^\circ$. It is one full turn, the amount you turn while walking once around the polygon.
The diagonals from $A$ cut the pentagon into 3 triangles. Drag the corners (keep it convex): the five angles in the readout always add to $3 \cdot 180^\circ = 540^\circ$.
Angle sums for convex polygons.
Sides $n$TrianglesInterior sumEach angle if regularEach exterior angle if regular
31$180^\circ$$60^\circ$$120^\circ$
42$360^\circ$$90^\circ$$90^\circ$
53$540^\circ$$108^\circ$$72^\circ$
64$720^\circ$$120^\circ$$60^\circ$
86$1080^\circ$$135^\circ$$45^\circ$
$n$$n - 2$$(n - 2) \cdot 180^\circ$$\frac{(n - 2) \cdot 180^\circ}{n}$$\frac{360^\circ}{n}$

Key idea

The interior angles of a convex $n$-gon add to $(n - 2) \cdot 180^\circ$. The exterior angles, one at each vertex, always add to $360^\circ$.

Worked example: An interior sum

Find the sum of the interior angles of a nonagon (9 sides).
  1. $(9 - 2) \cdot 180 = 7 \cdot 180 = 1260$.

Answer: $1260^\circ$

Worked example: Working backward from one angle

Each interior angle of a regular polygon measures $156^\circ$. How many sides does it have?
  1. Each exterior angle is $180 - 156 = 24^\circ$.
  2. The exterior angles add to $360^\circ$: $n = \frac{360}{24} = 15$.

Answer: 15 sides

Worked example: A missing angle

A hexagon has angles $110^\circ$, $135^\circ$, $120^\circ$, $140^\circ$, $95^\circ$ and $x^\circ$. Find $x$.
  1. Interior sum: $(6 - 2) \cdot 180 = 720$.
  2. Known angles: $110 + 135 + 120 + 140 + 95 = 600$.
  3. $x = 720 - 600 = 120$.

Answer: $x = 120$

Common mistake

Thinking the exterior angles add to more when there are more sides. The interior sum grows by $180^\circ$ with each new side, but the exterior sum stays $360^\circ$: more exterior angles, each one smaller. Check: a square has four $90^\circ$ exterior angles and a regular octagon has eight $45^\circ$ ones; both total $360^\circ$.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

Loading practice…

Builds on

Leads to

Sources and further reading

  • OpenStax Contemporary Mathematics, 10.4 Polygons, Perimeter, and Circumference
  • Euclid, <i>Elements</i>, Book I, Proposition 32 (with its corollaries)
@teddyrookbook GitHub