Algebra 1Expressions and Real NumbersN-RN.B.3

The Real Number System

Sort numbers into natural, whole, integer, rational and irrational.

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In Pre-Algebra you met irrational numbers like $\sqrt{2}$ and $\pi$. Algebra uses every kind of number at once, so it helps to know how the kinds fit together. Each group sits inside a bigger one, like nesting boxes.

  • Natural numbers: the counting numbers $1, 2, 3, \ldots$
  • Whole numbers: the natural numbers and $0$.
  • Integers: the whole numbers and their opposites: $\ldots, -2, -1, 0, 1, 2, \ldots$
  • Rational numbers: every number that can be written as $\frac{a}{b}$, where $a$ and $b$ are integers and $b \ne 0$. As decimals, they end ($0.75$) or repeat forever ($0.\overline{3}$).
  • Irrational numbers: real numbers that are not rational. Their decimals never end and never repeat, like $\sqrt{2} = 1.41421\ldots$ and $\pi$.
  • Real numbers: all of these together, every point on the number line.

Why it works

Why is every integer rational? Because any integer $n$ equals $\frac{n}{1}$, so $-4 = \frac{-4}{1}$. Why is a repeating decimal rational? Take $x = 0.\overline{3}$. Then $10x = 3.\overline{3}$, and subtracting gives $9x = 3$, so $x = \frac{1}{3}$. And why is $\sqrt{2}$ not rational? If $\sqrt{2} = \frac{a}{b}$ in lowest terms, then $a^2 = 2b^2$, so $a$ is even. Writing $a = 2k$ gives $b^2 = 2k^2$, so $b$ is even too. Both even contradicts lowest terms, so no such fraction exists.
Natural numbers sit inside the whole numbers, which sit inside the integers, which sit inside the rationals. The irrationals sit beside the rationals, and together they make the real numbers.

Worked examples

Worked example: A square root that simplifies

Which groups does $-\sqrt{16}$ belong to?
  1. Simplify first: $\sqrt{16} = 4$, so $-\sqrt{16} = -4$.
  2. $-4$ is an integer. It is not natural or whole, because it is negative.
  3. Every integer is rational: $-4 = \frac{-4}{1}$.
  4. Every rational number is real.

Answer: Integers, rational numbers, real numbers.

Worked example: A square root that does not

Which groups does $\sqrt{20}$ belong to?
  1. $20$ is not a perfect square: $4^2 = 16$ and $5^2 = 25$.
  2. So $\sqrt{20} = 4.4721\ldots$ never ends or repeats: it is irrational.
  3. Every irrational number is real.

Answer: Irrational numbers, real numbers.

Common mistake

Two classic slips: thinking every square root is irrational, and thinking a negative integer like $-4$ is not rational. $\sqrt{25} = 5$ is a natural number, and $-4 = \frac{-4}{1}$ is rational. Quick check: simplify the number first, then ask, “Can I write it as a fraction of two integers?”

Key idea

Natural $\subset$ whole $\subset$ integers $\subset$ rational, and rational plus irrational make up the real numbers. A number is rational exactly when it can be written as $\frac{a}{b}$ with integers $a$ and $b \ne 0$.

Practice

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Sources and further reading

  • OpenStax, Elementary Algebra 2e, section 1.8 The Real Numbers
  • Common Core State Standards for Mathematics, N-RN.B.3
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