Symbolic LogicPredicate Logic: Translation and Truth

Quantifier Negation

¬∀x Fx is equivalent to ∃x ¬Fx, and ¬∃x Fx to ∀x ¬Fx: moving a negation across a quantifier flips ∀ and ∃.

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A negation in front of a quantifier can be moved inside, switching the quantifier, much as De Morgan moves a negation through $\land$ and $\lor$ (De Morgan's Laws). This makes negated quantified sentences easy to read and to use in proofs. It builds on Translating Harder Quantified Sentences.

Quantifier negation (QN).
FormEquivalent formIn words
$\neg \forall x Fx$$\exists x\neg Fx$not everything is $F$ = something is not $F$
$\neg \exists x Fx$$\forall x\neg Fx$nothing is $F$ = everything is not $F$
$\forall x Fx$$\neg \exists x\neg Fx$everything is $F$ = nothing is not $F$
$\exists x Fx$$\neg \forall x\neg Fx$something is $F$ = not everything is not $F$

Key idea

Moving a $\neg$ across a quantifier switches it: $\neg \forall x Fx$ becomes $\exists x\neg Fx$, and $\neg \exists x Fx$ becomes $\forall x\neg Fx$, whatever formula stands in place of $Fx$. Then keep moving the $\neg$ inward with the rules you know (DM, and $\neg (p \to q)$ as $p \land \neg q$).

Why it works

"Not everything is red" is true exactly when there is at least one thing that is not red: a counterexample. "Nothing is red" is true exactly when each thing fails to be red. In a finite world, $\forall$ is a long conjunction (a is $F$ and b is $F$ and …) and $\exists$ a long disjunction, so quantifier negation is De Morgan's law stretched over the whole domain.
The sentences come in equivalent pairs: the first two agree in every world, and so do the last two. Here $c$ is a blue circle, which makes the first pair true.

Worked examples

Worked example: Not all

Rewrite $\neg \forall x(Cx \to Rx)$ with no $\neg$ in front of a quantifier.
  1. QN: $\exists x\neg (Cx \to Rx)$.
  2. A negated conditional is its antecedent and the negated consequent: $Cx \land \neg Rx$.

Answer: $\exists x(Cx \land \neg Rx)$: some circle is not red.

Worked example: No

Rewrite $\neg \exists x(Sx \land Rx)$.
  1. QN: $\forall x\neg (Sx \land Rx)$.
  2. DM: $\neg Sx \lor \neg Rx$, which is $Sx \to \neg Rx$ by Impl.

Answer: $\forall x(Sx \to \neg Rx)$: no square is red, an E statement.

Worked example: In English

What does $\neg \forall x(Px \to Mx)$ say, with $P$: pets and $M$: mammals?
  1. Not every pet is a mammal.
  2. QN: some pet is not a mammal.

Answer: Some pets are not mammals.

Common mistake

Moving the negation without switching the quantifier, or applying it to only part of the formula. $\neg \forall x Fx$ is not $\forall x\neg Fx$: "not everything is red" is much weaker than "nothing is red". The scope matters too: in $\neg \forall x Fx \to Ga$ the $\neg$ covers only $\forall x Fx$. Check the scope first, then switch $\forall$ and $\exists$ as the negation moves.

A handy pattern from these examples: once the negation has moved inside, a universal statement usually ends with an arrow inside it and an existential one with an "and". If your result has $\exists x(\ldots \to \ldots)$ or $\forall x(\ldots \land \ldots)$, look again; it is probably a slip.

In proofs, QN is a rule of replacement: it may be used on any part of a line, in either direction. It is often the first step when a premise begins with a negation, because the instantiation rules of the next unit need a quantifier in front.

More on Teddy Rook BookNegating Quantified Statements

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

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Sources and further reading

  • Patrick J. Hurley and Lori Watson, A Concise Introduction to Logic, 13th ed., section 8.3, Change of Quantifier Rule
  • forall x: Calgary, an open introduction to formal logic (P. D. Magnus, Tim Button and others; Open Logic Project), chapter on quantifier negation
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