Symbolic LogicPredicate Logic: Translation and Truth

Counterexample Worlds

Show an argument invalid by describing a small world where all its premises are true and its conclusion false.

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In statement logic, a counterexample to an argument is a row with true premises and a false conclusion (Validity by Truth Table). In predicate logic it is a world with true premises and a false conclusion. Building one is how you show a predicate argument is invalid, using what you learned in Truth in a Small World.

Key idea

A predicate-logic argument is invalid when some world makes every premise true and the conclusion false. To show invalidity, build such a world, then check each premise and the conclusion in it.

Why it works

Validity means no possible situation has true premises and a false conclusion. A world is one possible situation, so a single counterexample world settles invalidity. (Showing validity needs a proof, the topic of the next unit, since there are infinitely many worlds to rule out.) Small worlds with two or three objects are usually enough to break an invalid argument.
Premises: all circles are red; something is red. Conclusion: something is a circle. Change the world until it is a counterexample.

Worked examples

Worked example: The converse of an A statement

Show that $\forall x(Fx \to Gx)$ does not imply $\forall x(Gx \to Fx)$.
  1. We need every $F$ to be $G$, but some $G$ not to be $F$.
  2. World: one object $a$ that is $G$ and not $F$.
  3. Premise: true (there are no $F$ to fail). Conclusion: false ($a$ is $G$ but not $F$).

Answer: Invalid: the one-object world is a counterexample.

Worked example: Two separate witnesses

Show that $\exists x Fx$ and $\exists x Gx$ do not imply $\exists x(Fx \land Gx)$.
  1. World: $a$ is $F$ only; $b$ is $G$ only.
  2. Both premises are true; nothing is both, so the conclusion is false.

Answer: Invalid.

Worked example: In the picture

For the visual above, what world is a counterexample?
  1. The conclusion $\exists x Cx$ must be false: no circles.
  2. $\forall x(Cx \to Rx)$ is then true automatically.
  3. $\exists x Rx$ needs something red.

Answer: Any world with no circles and at least one red object, such as one red square.

Common mistake

Building a world where the conclusion is false but forgetting to check that every premise is still true in it. A world with a false premise shows nothing. After building, go back and evaluate each premise, one object at a time, as well as the conclusion.
  • Make the conclusion false first: that usually fixes a lot.
  • Then add or adjust objects until each premise is true.
  • Check everything again at the end.

Sometimes no world works, however hard you try. That is a hint, though not a proof, that the argument is valid. The next unit gives the tools to prove it: rules that let you reason from quantified premises directly.

Counterexample worlds are the predicate-logic twin of the short truth table method: start from what the counterexample needs and fill in the rest.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 3 XP.

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Sources and further reading

  • forall x: Calgary, an open introduction to formal logic (P. D. Magnus, Tim Button and others; Open Logic Project), chapter on using interpretations
  • Patrick J. Hurley and Lori Watson, A Concise Introduction to Logic, 13th ed., section 8.5, counterexample method
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