Symbolic LogicSymbols and Translation

The Five Connectives

Negation ¬, conjunction ∧, disjunction ∨, conditional → and biconditional ↔ build compound formulas from statement letters.

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In Simple and Compound Statements you split sentences into simple parts. Now we give those parts letters and the connectives symbols. We use lowercase letters $p$, $q$, $r$, $s$ for simple statements, and five connectives.

The five connectives of statement logic.
SymbolNameRead asExample
$\neg$negationnot$\neg p$
$\land$conjunctionand$p \land q$
$\lor$disjunctionor$p \lor q$
$\to$conditionalif … then$p \to q$
$\leftrightarrow$biconditionalif and only if$p \leftrightarrow q$

Key idea

A compound formula is built from statement letters with ¬, ∧, ∨, → and ↔. In $p \to q$, $p$ is the antecedent and $q$ the consequent; in $p \land q$ the parts are conjuncts; in $p \lor q$ they are disjuncts.

Why it works

Ordinary words like "and" and "or" carry extra hints of time, contrast or emotion. "She stood up and left" suggests an order; "but" suggests a contrast. Logic keeps only what matters for truth: whether each part is true or false. That is why one symbol, $\land$, can stand for "and", "but", "although" and "yet". Each symbol has one exact meaning, set by when the compound is true.

Every formula is either a single statement letter or is built from smaller formulas by one connective. So $p$, $\neg p$, $p \land q$ and $\neg (p \land q) \to r$ are all formulas, and each of the last three was made by one final step. That recipe is what lets a computer, or you, check any formula piece by piece.

The meanings are fixed by truth tables, which you will use throughout Truth Values of the Connectives. Here is the one surprise to remember now: logical "or" is inclusive. $p \lor q$ is true when $p$ is true, when $q$ is true, and also when both are true.

Disjunction is false in only one row: when both parts are false.

Worked examples

Worked example: Symbolize one connective

Let $p$: the library is open; $q$: the museum is open. Write "Either the library is open or the museum is open."
  1. "Either … or" is disjunction, $\lor$.
  2. The first disjunct is $p$, the second $q$.

Answer: $p \lor q$

Worked example: Two words, one symbol

With the same letters, write "The library is open, but the museum is not open."
  1. "But" claims both parts, so it is $\land$.
  2. The second part denies $q$: $\neg q$.
  3. Join them.

Answer: $p \land \neg q$

Worked example: Name the parts

In $(p \land q) \to r$, what are the antecedent and the consequent?
  1. The main connective is $\to$.
  2. Everything before it, $p \land q$, is the antecedent.
  3. Everything after it, $r$, is the consequent.

Answer: Antecedent $p \land q$, consequent $r$.

Common mistake

Reading $\lor$ as "one or the other but not both". In logic, $p \lor q$ is true when both parts are true. If you mean "exactly one", you must say so: $(p \lor q) \land \neg (p \land q)$. A quick check: "You may have cake or ice cream" is false only if you get neither.
You may type the connectives on a keyboard as ~ (not), & (and), v or | (or), -> (if … then) and <-> (if and only if). The answer box turns them into symbols.
More on Teddy Rook BookStatements and Connectives

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 1 XP.

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Sources and further reading

  • Patrick J. Hurley and Lori Watson, A Concise Introduction to Logic, 13th ed., section 6.1
  • forall x: Calgary, an open introduction to formal logic (P. D. Magnus, Tim Button and others; Open Logic Project), chapter on connectives
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