Ray's New Practical Arithmetic · Arts. 67–69 · Unit 7: Reduction of Compound Numbers

36. Square measure and the area of a rectangle

Goal: Your child finds the area of a rectangle by multiplying length by breadth, finds a missing side by dividing, and reduces square measures.

⏱ About 40 minutes · 7 steps

Open it at the Internet Archive ↗

You'll need

  • The book
  • A slate, small whiteboard or scrap paper
  • A notebook and pencil

What's in the book

Square measure: square inches, feet and yards, rods, acres and square miles, with reduction problems; then the rule for the area of a rectangle and its reverse, with carpet, floor and field problems.

The lesson, step by step

  1. Warm-up

    Mental: 4 × 3? 16 × 12? 5 × 4? Then ask: How many squares on a checkerboard 8 by 8?

  2. Square units

    Read:

    Square Measure is used in measuring any thing which has both length and breadth

    Draw a square foot on paper (12 inches each way) and rule it into inches. Count a row (12) and the rows (12): 144 square inches.

  3. The rule

    Read:

    A Rectangle is a figure having four sides and four right angles.

    Multiply the length by the breadth; the product will be the area.

    Work:

    In a floor 16 feet long and 12 feet wide, how many square feet?

    (192 square feet.)

  4. Backward

    Read:

    If the area of a rectangle be divided by either side, the quotient will be the other side.

    Work:

    A floor containing 132 square feet, is 11 feet wide: what is its length?

    (12 ft.)

  5. Guided practice

    Together:

    How many square yards of carpeting will cover a room 5 yards long and 4 yards wide?

    Then measure a real room or table and find its area.

  6. Independent practice

    Your child does reduction problems 1 to 10 and area problems 3 to 8, then the four "missing side" problems.

  7. Check and wrap-up

    Most answers are printed. Note for you: an acre is 160 square rods (about the size of a football field without the end zones).

Answers to the book's problems

Reduction problem 6: 960 sq. rd. = 6 A. Area problem 6 (field 35 rods by 32 rods): 1120 sq. rd. = 7 A.

Worked out for this site from the scan. If a number in your copy differs, trust the book.

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