MicroImperfect Competition

Nash Equilibrium and the Prisoner's Dilemma

In a Nash equilibrium no player can do better by changing alone, which is why cartels are hard to hold together.

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Many games have no dominant strategy (Payoff Matrices and Dominant Strategies). We still need a way to predict what happens. Practice the idea in the Game Theory course's Nash Equilibrium chapter.

Key idea

A Nash equilibrium is a pair of strategies in which each player's choice is a best response to the other's: no player can do better by changing their own strategy alone. To find one, mark each player's best response to every choice of the other; a cell where both payoffs are marked is a Nash equilibrium. A game can have one, several or none (in pure strategies).

Why it works

At a Nash equilibrium, nobody has regrets given what the others did, so there is no pull to move. In a prisoner's dilemma, each player has a dominant strategy to defect, so (defect, defect) is the Nash equilibrium, even though both would be better off cooperating. That explains why cartels are hard to keep together: each member gains by cheating on the agreement, whatever the others do.
A prisoner's dilemma. Mark each player's best responses, then Check: the only cell with both payoffs marked is the Nash equilibrium, and it's worse for both than the cell they would agree on.

Worked example: A cartel breaks down

Two firms agree to keep output low. Payoffs (A, B) in millions: both Keep (10, 10); A Cheats and B Keeps (14, 4); A Keeps and B Cheats (4, 14); both Cheat (6, 6). Find the Nash equilibrium.
  1. A's best responses: against Keep, Cheat (14 > 10); against Cheat, Cheat (6 > 4).
  2. B's best responses are the same by symmetry.
  3. Only (Cheat, Cheat) has both payoffs marked: the Nash equilibrium, at 6 each, worse than the 10 each from keeping the deal.

Answer: (Cheat, Cheat).

Worked example: Two equilibria

Two friends pick a café without talking. Both at Café A: (3, 3); both at Café B: (2, 2); different cafés: (0, 0). Find the Nash equilibria.
  1. If the other goes to A, your best response is A (3 > 0); if the other goes to B, it's B (2 > 0).
  2. Both (A, A) and (B, B) are Nash equilibria: neither friend wants to switch alone.

Answer: (A, A) and (B, B).

Common mistake

Thinking a Nash equilibrium must be the best outcome for both players. It's only stable: no one can gain by changing alone. In a prisoner's dilemma, both would gain by changing together, but neither can trust the other to. Check a candidate cell by asking each player in turn: "holding the other fixed, would you switch?"
Repeated play changes things: firms that meet again and again can sometimes keep cooperating, because cheating today invites punishment tomorrow. That is the subject of the Game Theory course's repeated games chapter.
Go deeper in the Business coursesNash Equilibrium

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

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Sources and further reading

  • OpenStax Principles of Microeconomics 3e, 10.2 Oligopoly
  • MIT OpenCourseWare 14.01 Principles of Microeconomics (scope and sequence)
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