GeologyLandscapes

Landslides and Slope Stability

A slope fails when the downhill pull beats the friction and strength holding it; water and steeper slopes tip the balance.

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Landslides, rockfalls, slumps and creeping soil are all mass wasting: rock and soil moving downhill under gravity, with no river or glacier carrying them. In Erosion and Deposition gravity was in the background; here it is the whole story, and right-triangle trigonometry tells us when a slope gives way.

Why it works

Picture a block of soil on a slope at angle $\theta$. Its weight $W$ splits into two parts: one pulling it down the slope, $W\sin\theta$, and one pressing it into the slope, $W\cos\theta$. Friction resists sliding, and it grows with the pressing force: friction $= W\cos\theta \tan\varphi$, where $\varphi$ is the material's friction angle (the steepest angle it can rest at). The factor of safety compares them: $FS = \dfrac{\text{resisting}}{\text{driving}} = \dfrac{W\cos\theta\tan\varphi}{W\sin\theta} = \dfrac{\tan\varphi}{\tan\theta}$ for dry, loose material. Above 1 the slope holds; below 1 it fails. Steepen the slope and the pull grows while the friction shrinks.

Key idea

A slope fails when the downhill pull beats the friction and strength holding it: $FS = \dfrac{\tan\varphi}{\tan\theta}$ for dry, loose material, with failure below 1. Water filling the pores lowers the friction and can cut FS roughly in half.
A slope with its forces. Steepen it, or soak it with water, and watch the factor of safety fall.

Worked examples

Worked example: Is it stable?

Dry gravel with a friction angle of $35^\circ$ sits on a $30^\circ$ slope. Find FS.
  1. $FS = \dfrac{\tan 35^\circ}{\tan 30^\circ} = \dfrac{0.700}{0.577} \approx 1.21$.
  2. Above 1: stable, but without much margin.

Answer: $FS \approx 1.21$: stable.

Worked example: After heavy rain

The same slope becomes soaked, with water seeping down parallel to the surface. Then $FS \approx \dfrac{\gamma_{sat} - \gamma_w}{\gamma_{sat}}\cdot\dfrac{\tan\varphi}{\tan\theta}$, with soaked soil $20\,\text{kN/m}^3$ and water $9.8\,\text{kN/m}^3$. Find FS.
  1. $\dfrac{20 - 9.8}{20} = 0.51$.
  2. $FS \approx 0.51 \times 1.21 \approx 0.62$. Below 1: the slope fails.

Answer: $FS \approx 0.62$: it fails.

Common mistake

It is natural to think water makes slopes fail mainly by adding weight. The weight adds a little, but the bigger effect is that water under pressure in the pores pushes the grains apart, so they press together less and friction drops. Check with the formula: the water term reduces the friction part, not the pull.

Practice

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This is one of the top rungs of Geology.

Sources and further reading

  • OpenStax, College Physics 2e, section 5.1, Friction
  • MIT OpenCourseWare, 12.001 Introduction to Geology
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