Gen Chem 2Coordination Compounds

Naming Coordination Compounds

Name the ligands in alphabetical order with prefixes, then the metal and its oxidation state.

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Once you can find the parts of a coordination compound, its name follows a fixed recipe. The name tells a chemist every ligand, the metal and its oxidation state.

Key idea

Name the cation first, then the anion, as for any salt. Inside the complex: ligands in alphabetical order (ignoring number prefixes), each with a prefix for how many (di-, tri-, tetra-; or bis-, tris- for ligands like ethylenediamine), then the metal with its oxidation state in Roman numerals. If the complex is an anion, the metal takes the ending -ate.

Why it works

The rules make every name unique and reversible: from the name you can write the formula, and back. Anionic ligands end in -o (current IUPAC names end in -ido: chlorido, cyanido; older books use chloro, cyano). Neutral ligands have special names: ammine ($\mathrm{NH_3}$), aqua ($\mathrm{H_2O}$), carbonyl (CO). The -ate ending signals a negative complex, just as sulfate and nitrate are anions. Some -ate names use the Latin root: ferrate (Fe), cuprate (Cu), argentate (Ag), plumbate (Pb), aurate (Au), stannate (Sn).
Common ligand names (older forms in parentheses).
LigandNameLigandName
$\mathrm{NH_3}$ammine$\mathrm{Cl^-}$chlorido (chloro)
$\mathrm{H_2O}$aqua$\mathrm{CN^-}$cyanido (cyano)
$\mathrm{CO}$carbonyl$\mathrm{OH^-}$hydroxido (hydroxo)
enethylenediamine$\mathrm{C_2O_4^{2-}}$oxalato
The hexacyanidoferrate(III) ion, $\mathrm{[Fe(CN)_6]^{3-}}$: an anion, so iron becomes "ferrate."

Worked examples

Worked example: A complex cation

Name $\mathrm{[Co(NH_3)_4Cl_2]Cl}$.
  1. Complex cation $\mathrm{[Co(NH_3)_4Cl_2]^+}$; anion chloride. Cobalt: $x + 0 + 2(-1) = +1$, so Co(III).
  2. Ligands alphabetically: ammine (a) before chlorido (c): tetraammine, dichlorido.
  3. Name: tetraamminedichloridocobalt(III) chloride.

Answer: Tetraamminedichloridocobalt(III) chloride.

Worked example: A complex anion

Name $\mathrm{K_3[Fe(CN)_6]}$.
  1. Cation: potassium. Complex anion $\mathrm{[Fe(CN)_6]^{3-}}$: $x + 6(-1) = -3$, so Fe(III).
  2. Six cyanido ligands: hexacyanido. Anion, so iron becomes ferrate.
  3. Name: potassium hexacyanidoferrate(III) (older: potassium hexacyanoferrate(III)).

Answer: Potassium hexacyanidoferrate(III).

Worked example: From name to formula

Write the formula of diamminesilver(I) nitrate.
  1. Complex: Ag(I) with two $\mathrm{NH_3}$: $\mathrm{[Ag(NH_3)_2]^+}$.
  2. One nitrate balances it: $\mathrm{[Ag(NH_3)_2]NO_3}$.

Answer: $\mathrm{[Ag(NH_3)_2]NO_3}$.

Formulas follow their own order: inside the brackets, the metal comes first, then the ligands. Many books list neutral ligands before anionic ones, as in $\mathrm{[Co(NH_3)_4Cl_2]^+}$; current IUPAC rules list ligands alphabetically by their formulas. Either way, the brackets enclose the complex and its charge sits outside them.

Common mistake

Alphabetizing ligands by their number prefixes, which would put "dichlorido" before "tetraammine" because d comes before t. Prefixes are ignored: compare "chlorido" with "ammine." Also, forgetting the -ate ending for a metal in a complex anion. Check: if the brackets carry a negative charge, the metal's name must end in -ate.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

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This is one of the top rungs of General Chemistry 2.

Sources and further reading

  • OpenStax Chemistry 2e, Section 19.2 Coordination Chemistry of Transition Metals
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