Gen Chem 1Reactions in Solution

Oxidation and Reduction

Oxidation is the loss of electrons and reduction is the gain; one never happens without the other.

Not started Jump to practice

With Oxidation Numbers you can see electrons move. In Predicting Single Replacements a zinc strip in copper sulfate solution grew a coat of copper; now we can say exactly what happened to the electrons.

Key idea

Oxidation is the loss of electrons (oxidation number goes up). Reduction is the gain of electrons (oxidation number goes down). They always happen together, and the electrons lost equal the electrons gained. The substance that is reduced is the oxidizing agent (it takes electrons from the other); the substance that is oxidized is the reducing agent.

Why it works

Electrons can't vanish or appear from nowhere, so every electron one substance loses, another must gain: there is no oxidation without reduction. The names of the agents describe what they do to the other substance. Copper(II) ions oxidize zinc by taking its electrons, so $\mathrm{Cu^{2+}}$ is the oxidizing agent, and in doing so it is itself reduced. A memory aid: OIL RIG, oxidation is loss, reduction is gain.
The zinc–copper reaction split into two beakers: zinc loses electrons (oxidation) and copper ions gain them (reduction), with the electrons traveling through the wire. You will study these cells in General Chemistry 2.

Worked example: Zinc and copper ions

In $\mathrm{Zn(s)} + \mathrm{Cu^{2+}(aq)} \to \mathrm{Zn^{2+}(aq)} + \mathrm{Cu(s)}$, identify what is oxidized, what is reduced, and the two agents.
  1. Zn: $0 \to +2$, loses 2 electrons: oxidized. So Zn is the reducing agent.
  2. Cu: $+2 \to 0$, gains 2 electrons: reduced. So $\mathrm{Cu^{2+}}$ is the oxidizing agent.
  3. 2 electrons transferred per zinc atom.

Answer: Zn oxidized (reducing agent); $\mathrm{Cu^{2+}}$ reduced (oxidizing agent).

Worked example: Burning magnesium

In $2\,\mathrm{Mg} + \mathrm{O_2} \to 2\,\mathrm{MgO}$, how many electrons are transferred as written?
  1. Mg: $0 \to +2$, 2 electrons lost per atom; 2 atoms: 4 electrons.
  2. O: $0 \to -2$, 2 gained per atom; 2 atoms: 4 electrons. They match.

Answer: 4 electrons; Mg is oxidized and $\mathrm{O_2}$ is reduced (the oxidizing agent).

Worked example: Is it redox?

Is $\mathrm{AgNO_3} + \mathrm{NaCl} \to \mathrm{AgCl} + \mathrm{NaNO_3}$ a redox reaction?
  1. Ag stays $+1$, Cl stays $-1$, Na stays $+1$, N stays $+5$ and O stays $-2$.
  2. No oxidation number changes.

Answer: No: it is a precipitation, not a redox reaction.

Common mistake

Calling the substance that gets oxidized the oxidizing agent. The agent is named for what it does to its partner: the oxidizing agent causes oxidation in something else, by taking its electrons, so it is the one reduced. Check: the oxidizing agent's oxidation number goes down.

Practice

Pass with 3 right answers, the last 2 in a row. Each right answer earns 2 XP.

Loading practice…

Builds on

Leads to

Sources and further reading

  • OpenStax Chemistry 2e, 4.2 Classifying Chemical Reactions (oxidation–reduction reactions)
  • College Board, AP Chemistry Course and Exam Description (effective fall 2024), Unit 4: Chemical Reactions
@teddyrookbook GitHub