Gen Chem 1Explaining Periodic Trends

Shielding and Effective Nuclear Charge

Core electrons screen the nucleus, so a valence electron feels roughly the protons minus the core electrons.

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Coulomb's Law in Atoms needs one more piece. A valence electron doesn't feel the nucleus's full charge, because the inner electrons, from your Electron Configurations, sit between them and cancel part of it. The charge left over is the effective nuclear charge, $Z_\text{eff}$.

Key idea

$$Z_\text{eff} \approx Z - (\text{number of core electrons})$$ Core (inner-shell) electrons shield the nucleus almost completely; electrons in the same shell shield each other only a little. So across a period $Z_\text{eff}$ rises by about one per element, and down a group it stays about the same while the distance grows.

Why it works

A core electron spends nearly all its time much closer to the nucleus than a valence electron does, so from outside it looks like it sits on the nucleus and cancels one proton. An electron in the same shell is as often farther out as closer in, so it cancels very little. Sodium ($1s^2 2s^2 2p^6 3s^1$) has 10 core electrons: $Z_\text{eff} \approx 11 - 10 = 1$. Chlorine ($[\text{Ne}]\,3s^2 3p^5$) has the same 10 core electrons and 17 protons: $Z_\text{eff} \approx 7$. Its valence electrons feel about seven times the pull, at a similar shell, so chlorine's atom is smaller and much harder to ionize.
Sodium and chlorine side by side. The shaded core hides 10 protons in each; chlorine's valence electrons feel about 7 units of charge to sodium's 1, and are pulled in closer.
Across a period $Z_\text{eff}$ rises and the radius shrinks; down a group $Z_\text{eff}$ stays near the same and the radius grows. (Radii: Cordero et al., 2008.)
Element$Z$Core electrons$Z_\text{eff}$ (simple)Covalent radius
Li321128 pm
C62476 pm
F92757 pm
Na11101166 pm
Cl17107102 pm
K19181203 pm

Worked example: Finding Z_eff

Estimate $Z_\text{eff}$ for a valence electron of phosphorus ($Z = 15$).
  1. Configuration: $[\text{Ne}]\,3s^2\,3p^3$. The core is the neon part: 10 electrons.
  2. $Z_\text{eff} \approx 15 - 10 = 5$.

Answer: About $+5$.

Worked example: Using Z_eff to compare sizes

Which atom is smaller, magnesium or sulfur? Explain with $Z_\text{eff}$.
  1. Both have valence electrons in shell 3 and a neon core of 10 electrons.
  2. Mg: $Z_\text{eff} \approx 12 - 10 = 2$. S: $Z_\text{eff} \approx 16 - 10 = 6$.
  3. Sulfur's valence electrons feel three times the pull and are drawn in closer.

Answer: Sulfur (105 pm against 141 pm).

Common mistake

Thinking electrons in the same shell shield each other as well as core electrons do. If they did, every element in a period would have $Z_\text{eff} = 1$, and atoms would not shrink from sodium to argon, though they clearly do. Count only the inner-shell electrons as shielding. Check: within one period, the simple $Z_\text{eff}$ should equal the number of valence electrons for main-group elements.
The simple formula overstates the effect a little, because same-shell electrons do shield somewhat. Slater's rules, a better estimate, give $Z_\text{eff} = 2.2$ for sodium's 3s electron and $6.1$ for chlorine's 3p electrons. The trend is the same.

Practice

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Sources and further reading

  • OpenStax Chemistry 2e, 6.5 Periodic Variations in Element Properties
  • College Board, AP Chemistry Course and Exam Description (effective fall 2024), Unit 1: Atomic Structure and Properties
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